Integrand size = 21, antiderivative size = 123 \[ \int \sqrt {b \sec (e+f x)} \sin ^6(e+f x) \, dx=\frac {80 \sqrt {\cos (e+f x)} \operatorname {EllipticF}\left (\frac {1}{2} (e+f x),2\right ) \sqrt {b \sec (e+f x)}}{77 f}-\frac {40 b \sin (e+f x)}{77 f \sqrt {b \sec (e+f x)}}-\frac {20 b \sin ^3(e+f x)}{77 f \sqrt {b \sec (e+f x)}}-\frac {2 b \sin ^5(e+f x)}{11 f \sqrt {b \sec (e+f x)}} \]
-40/77*b*sin(f*x+e)/f/(b*sec(f*x+e))^(1/2)-20/77*b*sin(f*x+e)^3/f/(b*sec(f *x+e))^(1/2)-2/11*b*sin(f*x+e)^5/f/(b*sec(f*x+e))^(1/2)+80/77*(cos(1/2*f*x +1/2*e)^2)^(1/2)/cos(1/2*f*x+1/2*e)*EllipticF(sin(1/2*f*x+1/2*e),2^(1/2))* cos(f*x+e)^(1/2)*(b*sec(f*x+e))^(1/2)/f
Time = 0.34 (sec) , antiderivative size = 73, normalized size of antiderivative = 0.59 \[ \int \sqrt {b \sec (e+f x)} \sin ^6(e+f x) \, dx=\frac {\sqrt {b \sec (e+f x)} \left (1280 \sqrt {\cos (e+f x)} \operatorname {EllipticF}\left (\frac {1}{2} (e+f x),2\right )-435 \sin (2 (e+f x))+68 \sin (4 (e+f x))-7 \sin (6 (e+f x))\right )}{1232 f} \]
(Sqrt[b*Sec[e + f*x]]*(1280*Sqrt[Cos[e + f*x]]*EllipticF[(e + f*x)/2, 2] - 435*Sin[2*(e + f*x)] + 68*Sin[4*(e + f*x)] - 7*Sin[6*(e + f*x)]))/(1232*f )
Time = 0.63 (sec) , antiderivative size = 133, normalized size of antiderivative = 1.08, number of steps used = 10, number of rules used = 10, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.476, Rules used = {3042, 3107, 3042, 3107, 3042, 3107, 3042, 4258, 3042, 3120}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
\(\displaystyle \int \sin ^6(e+f x) \sqrt {b \sec (e+f x)} \, dx\) |
\(\Big \downarrow \) 3042 |
\(\displaystyle \int \frac {\sqrt {b \sec (e+f x)}}{\csc (e+f x)^6}dx\) |
\(\Big \downarrow \) 3107 |
\(\displaystyle \frac {10}{11} \int \sqrt {b \sec (e+f x)} \sin ^4(e+f x)dx-\frac {2 b \sin ^5(e+f x)}{11 f \sqrt {b \sec (e+f x)}}\) |
\(\Big \downarrow \) 3042 |
\(\displaystyle \frac {10}{11} \int \frac {\sqrt {b \sec (e+f x)}}{\csc (e+f x)^4}dx-\frac {2 b \sin ^5(e+f x)}{11 f \sqrt {b \sec (e+f x)}}\) |
\(\Big \downarrow \) 3107 |
\(\displaystyle \frac {10}{11} \left (\frac {6}{7} \int \sqrt {b \sec (e+f x)} \sin ^2(e+f x)dx-\frac {2 b \sin ^3(e+f x)}{7 f \sqrt {b \sec (e+f x)}}\right )-\frac {2 b \sin ^5(e+f x)}{11 f \sqrt {b \sec (e+f x)}}\) |
\(\Big \downarrow \) 3042 |
\(\displaystyle \frac {10}{11} \left (\frac {6}{7} \int \frac {\sqrt {b \sec (e+f x)}}{\csc (e+f x)^2}dx-\frac {2 b \sin ^3(e+f x)}{7 f \sqrt {b \sec (e+f x)}}\right )-\frac {2 b \sin ^5(e+f x)}{11 f \sqrt {b \sec (e+f x)}}\) |
\(\Big \downarrow \) 3107 |
\(\displaystyle \frac {10}{11} \left (\frac {6}{7} \left (\frac {2}{3} \int \sqrt {b \sec (e+f x)}dx-\frac {2 b \sin (e+f x)}{3 f \sqrt {b \sec (e+f x)}}\right )-\frac {2 b \sin ^3(e+f x)}{7 f \sqrt {b \sec (e+f x)}}\right )-\frac {2 b \sin ^5(e+f x)}{11 f \sqrt {b \sec (e+f x)}}\) |
\(\Big \downarrow \) 3042 |
\(\displaystyle \frac {10}{11} \left (\frac {6}{7} \left (\frac {2}{3} \int \sqrt {b \csc \left (e+f x+\frac {\pi }{2}\right )}dx-\frac {2 b \sin (e+f x)}{3 f \sqrt {b \sec (e+f x)}}\right )-\frac {2 b \sin ^3(e+f x)}{7 f \sqrt {b \sec (e+f x)}}\right )-\frac {2 b \sin ^5(e+f x)}{11 f \sqrt {b \sec (e+f x)}}\) |
\(\Big \downarrow \) 4258 |
\(\displaystyle \frac {10}{11} \left (\frac {6}{7} \left (\frac {2}{3} \sqrt {\cos (e+f x)} \sqrt {b \sec (e+f x)} \int \frac {1}{\sqrt {\cos (e+f x)}}dx-\frac {2 b \sin (e+f x)}{3 f \sqrt {b \sec (e+f x)}}\right )-\frac {2 b \sin ^3(e+f x)}{7 f \sqrt {b \sec (e+f x)}}\right )-\frac {2 b \sin ^5(e+f x)}{11 f \sqrt {b \sec (e+f x)}}\) |
\(\Big \downarrow \) 3042 |
\(\displaystyle \frac {10}{11} \left (\frac {6}{7} \left (\frac {2}{3} \sqrt {\cos (e+f x)} \sqrt {b \sec (e+f x)} \int \frac {1}{\sqrt {\sin \left (e+f x+\frac {\pi }{2}\right )}}dx-\frac {2 b \sin (e+f x)}{3 f \sqrt {b \sec (e+f x)}}\right )-\frac {2 b \sin ^3(e+f x)}{7 f \sqrt {b \sec (e+f x)}}\right )-\frac {2 b \sin ^5(e+f x)}{11 f \sqrt {b \sec (e+f x)}}\) |
\(\Big \downarrow \) 3120 |
\(\displaystyle \frac {10}{11} \left (\frac {6}{7} \left (\frac {4 \sqrt {\cos (e+f x)} \operatorname {EllipticF}\left (\frac {1}{2} (e+f x),2\right ) \sqrt {b \sec (e+f x)}}{3 f}-\frac {2 b \sin (e+f x)}{3 f \sqrt {b \sec (e+f x)}}\right )-\frac {2 b \sin ^3(e+f x)}{7 f \sqrt {b \sec (e+f x)}}\right )-\frac {2 b \sin ^5(e+f x)}{11 f \sqrt {b \sec (e+f x)}}\) |
(-2*b*Sin[e + f*x]^5)/(11*f*Sqrt[b*Sec[e + f*x]]) + (10*((-2*b*Sin[e + f*x ]^3)/(7*f*Sqrt[b*Sec[e + f*x]]) + (6*((4*Sqrt[Cos[e + f*x]]*EllipticF[(e + f*x)/2, 2]*Sqrt[b*Sec[e + f*x]])/(3*f) - (2*b*Sin[e + f*x])/(3*f*Sqrt[b*S ec[e + f*x]])))/7))/11
3.4.78.3.1 Defintions of rubi rules used
Int[(csc[(e_.) + (f_.)*(x_)]*(a_.))^(m_)*((b_.)*sec[(e_.) + (f_.)*(x_)])^(n _.), x_Symbol] :> Simp[b*(a*Csc[e + f*x])^(m + 1)*((b*Sec[e + f*x])^(n - 1) /(a*f*(m + n))), x] + Simp[(m + 1)/(a^2*(m + n)) Int[(a*Csc[e + f*x])^(m + 2)*(b*Sec[e + f*x])^n, x], x] /; FreeQ[{a, b, e, f, n}, x] && LtQ[m, -1] && NeQ[m + n, 0] && IntegersQ[2*m, 2*n]
Int[1/Sqrt[sin[(c_.) + (d_.)*(x_)]], x_Symbol] :> Simp[(2/d)*EllipticF[(1/2 )*(c - Pi/2 + d*x), 2], x] /; FreeQ[{c, d}, x]
Int[(csc[(c_.) + (d_.)*(x_)]*(b_.))^(n_), x_Symbol] :> Simp[(b*Csc[c + d*x] )^n*Sin[c + d*x]^n Int[1/Sin[c + d*x]^n, x], x] /; FreeQ[{b, c, d}, x] && EqQ[n^2, 1/4]
Result contains complex when optimal does not.
Time = 4.21 (sec) , antiderivative size = 179, normalized size of antiderivative = 1.46
method | result | size |
default | \(\frac {2 \left (-7 \left (\cos ^{5}\left (f x +e \right )\right ) \sin \left (f x +e \right )+40 i \sqrt {\frac {1}{\cos \left (f x +e \right )+1}}\, \sqrt {\frac {\cos \left (f x +e \right )}{\cos \left (f x +e \right )+1}}\, F\left (i \left (\cot \left (f x +e \right )-\csc \left (f x +e \right )\right ), i\right ) \cos \left (f x +e \right )+40 i \sqrt {\frac {1}{\cos \left (f x +e \right )+1}}\, \sqrt {\frac {\cos \left (f x +e \right )}{\cos \left (f x +e \right )+1}}\, F\left (i \left (\cot \left (f x +e \right )-\csc \left (f x +e \right )\right ), i\right )+24 \left (\cos ^{3}\left (f x +e \right )\right ) \sin \left (f x +e \right )-37 \sin \left (f x +e \right ) \cos \left (f x +e \right )\right ) \sqrt {b \sec \left (f x +e \right )}}{77 f}\) | \(179\) |
2/77/f*(-7*cos(f*x+e)^5*sin(f*x+e)+40*I*(1/(cos(f*x+e)+1))^(1/2)*(cos(f*x+ e)/(cos(f*x+e)+1))^(1/2)*EllipticF(I*(cot(f*x+e)-csc(f*x+e)),I)*cos(f*x+e) +40*I*(1/(cos(f*x+e)+1))^(1/2)*(cos(f*x+e)/(cos(f*x+e)+1))^(1/2)*EllipticF (I*(cot(f*x+e)-csc(f*x+e)),I)+24*cos(f*x+e)^3*sin(f*x+e)-37*sin(f*x+e)*cos (f*x+e))*(b*sec(f*x+e))^(1/2)
Result contains higher order function than in optimal. Order 9 vs. order 4.
Time = 0.10 (sec) , antiderivative size = 106, normalized size of antiderivative = 0.86 \[ \int \sqrt {b \sec (e+f x)} \sin ^6(e+f x) \, dx=-\frac {2 \, {\left ({\left (7 \, \cos \left (f x + e\right )^{5} - 24 \, \cos \left (f x + e\right )^{3} + 37 \, \cos \left (f x + e\right )\right )} \sqrt {\frac {b}{\cos \left (f x + e\right )}} \sin \left (f x + e\right ) + 20 i \, \sqrt {2} \sqrt {b} {\rm weierstrassPInverse}\left (-4, 0, \cos \left (f x + e\right ) + i \, \sin \left (f x + e\right )\right ) - 20 i \, \sqrt {2} \sqrt {b} {\rm weierstrassPInverse}\left (-4, 0, \cos \left (f x + e\right ) - i \, \sin \left (f x + e\right )\right )\right )}}{77 \, f} \]
-2/77*((7*cos(f*x + e)^5 - 24*cos(f*x + e)^3 + 37*cos(f*x + e))*sqrt(b/cos (f*x + e))*sin(f*x + e) + 20*I*sqrt(2)*sqrt(b)*weierstrassPInverse(-4, 0, cos(f*x + e) + I*sin(f*x + e)) - 20*I*sqrt(2)*sqrt(b)*weierstrassPInverse( -4, 0, cos(f*x + e) - I*sin(f*x + e)))/f
Timed out. \[ \int \sqrt {b \sec (e+f x)} \sin ^6(e+f x) \, dx=\text {Timed out} \]
\[ \int \sqrt {b \sec (e+f x)} \sin ^6(e+f x) \, dx=\int { \sqrt {b \sec \left (f x + e\right )} \sin \left (f x + e\right )^{6} \,d x } \]
\[ \int \sqrt {b \sec (e+f x)} \sin ^6(e+f x) \, dx=\int { \sqrt {b \sec \left (f x + e\right )} \sin \left (f x + e\right )^{6} \,d x } \]
Timed out. \[ \int \sqrt {b \sec (e+f x)} \sin ^6(e+f x) \, dx=\int {\sin \left (e+f\,x\right )}^6\,\sqrt {\frac {b}{\cos \left (e+f\,x\right )}} \,d x \]